Third Order Cube 320A5C
1. **Problem:** Solve the differential equation $$(D^3 + 3D^2 + 3D + 1) y = 0$$ where $D = \frac{d}{dx}$.
2. **Characteristic equation:** Replace $D$ by $r$ to get
$$r^3 + 3r^2 + 3r + 1 = 0$$
3. **Recognize the pattern:** This is a perfect cube expansion:
$$r^3 + 3r^2 + 3r + 1 = (r + 1)^3 = 0$$
4. **Roots:** The root is $r = -1$ with multiplicity 3.
5. **General solution:** For repeated roots $r$ of multiplicity $m$, the solution is
$$y = (C_1 + C_2 x + C_3 x^2) e^{rx}$$
6. **Apply roots:** Here,
$$y = (C_1 + C_2 x + C_3 x^2) e^{-x}$$
**Final answer:**
$$\boxed{y = (C_1 + C_2 x + C_3 x^2) e^{-x}}$$