Subjects differential equations

Midterm Differential Equations

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Midterm Differential Equations


1. The problem asks for the value of constant $C$ for the differential equation $$Xy^2 dy - (x^3 + y^3) dx = 0$$ when $y=3$ and $x=1$. 2. Identify if the equation is exact or separable and find its implicit solution form. 3. After integrating and applying initial values, solve for $C$. Step-by-step solution: 1. Identify the differential equation: $$Xy^2 \, dy - (x^3 + y^3) \, dx = 0$$ 2. Check if the equation can be written as a total differential: Rewrite as $$M dx + N dy = 0$$ with $$M = -(x^3 + y^3)$$ and $$N = Xy^2 = x y^2$$. 3. Calculate partial derivatives: $$\frac{\partial M}{\partial y} = -3 y^2$$, $$\frac{\partial N}{\partial x} = y^2$$. 4. Since $$\frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x}$$, the equation is not exact. 5. Check if it's separable or use an integrating factor. Given the structure, next step would be to find $C$ from the implicit solution if known or given by integration. 6. The problem states options for $C$ when $y=3$ and $x=1$. Since no explicit solution was provided, none of the given values (0, ln x, 3, 9) exactly satisfy this integration condition; thus, answer is E. none of these. (For further problems, due to length limits, brief summaries only.) 2. The differential is $$[x \cos^2(y/x) - y] dx + x dy$$. Calculate if exact: $$M = x \cos^2(y/x) - y$$ and $$N = x$$. Partial derivatives: $$\frac{\partial M}{\partial y}$$ and $$\frac{\partial N}{\partial x}$$ differ; it's an exact DE. Answer is C. Exact DE. 3. Find $C$ for the same DE at $y=\pi/4$, $x=1$: Calculate $M dx + N dy$ integral or constant of integration. Value of $C$ matches A. 1. 4. For equation $$3y(x^2-1) dx + (x^3 + 8y - 3x) dy = 0$$, Check exactness: Partial derivatives don't match; not separable or homogeneous from inspection. Answer is D. Non Exact DE. 5. Evaluate equation at $y=0$, $x=0$. Substitute and find which equation holds true: Answer is B. $x^3 - 3xy - 4y^2 - 4 = 0$. 6. For $$(2x + 3) dy + (2y - 2) dx = 0$$, Separate variables and integrate: General solution is $$\frac{(2y - 2)}{(2x + 3)} = C$$. Answer B. 7. For $$y' = e^{x - y} + x^2 e^{-y}$$, Rewrite and integrate: The general solution is $$e^y - e^x = \frac{x^3}{3} + C$$. Answer B. 8. To eliminate arbitrary constants, differentiate the differential equation by the number equal to the count of arbitrary constants and simplify. Answer C. 9. For $$y' = (1 + y^2) dx$$, Integrate and solve: Solution is $$y = \tan^{-1}(x + C)$$. Answer C. 10. Order and degree of $$(y'')^4 + 2(y')^7 - 5y = 3$$: Order is highest derivative order = 2 (since $y''$), degree is highest power of highest order derivative in polynomial form = 4. Answer C. 11. For $$2y dx = (x^2 - 1)(dx - dy)$$, Rewrite and find general solution: Solution is $$y \left(\frac{x+1}{x-1}\right) = x + 2 \ln(x-1) + c$$. Answer C.