1. The problem involves understanding the relationship between the variable labeled "li" and the volume values given. 2. From the data, it appears "li" increases by 0.1 each step, and volume increases accordingly. 3. To analyze this, we can consider the volume as a function of "li", denoted as $V(li)$. 4. The data suggests a linear or near-linear relationship, so we can use the formula for a linear function: $$V(li) = m \times li + b$$ where $m$ is the slope and $b$ is the intercept. 5. To find $m$, use two points, for example, $(7.0, 924.000)$ and $(7.1, 942.480)$: $$m = \frac{942.480 - 924.000}{7.1 - 7.0} = \frac{18.48}{0.1} = 184.8$$ 6. To find $b$, use one point and the slope: $$924.000 = 184.8 \times 7.0 + b \Rightarrow b = 924.000 - 1293.6 = -369.6$$ 7. Thus, the approximate linear function is: $$V(li) = 184.8 \times li - 369.6$$ 8. This function can be used to estimate volume for any given "li" within the data range. 9. Note: The actual data may be more complex, but this linear approximation fits the initial points well.