Average Value 1474B3
1. The problem is to find the average value of the given data points in the "getData(...an") (W)" column and check if it lies between 125 and 167.
2. The average value $\bar{x}$ of a set of $n$ data points $x_1, x_2, \ldots, x_n$ is given by the formula:
$$\bar{x} = \frac{1}{n} \sum_{i=1}^n x_i$$
3. We sum all the values in the "getData" column and divide by the total number of data points.
4. Converting all values to a consistent unit (watts) and summing:
- Values range from about $18.7 \times 10^{-12}$ to $68.15 \times 10^{-6}$ watts.
- Summing all 32 values (approximate):
$$\text{Sum} \approx (17.75 + 1.691 + 2.312 + 2.618 + 4.864 + 9.642 + 22.74 + 293.1 + 4304 + 13710 + 29750 + 50670 + 64230 + 68640 + 69430 + 69070 + 68420 + 68150 + 68050 + 67880 + 67660 + 67620 + 68170 + 67800 + 63390 + 55510 + 45820 + 34020 + 19510 + 9039 + 4401) \times 10^{-9}$$
5. Calculate the sum inside parentheses:
$$= 17.75 + 1.691 + 2.312 + 2.618 + 4.864 + 9.642 + 22.74 + 293.1 + 4304 + 13710 + 29750 + 50670 + 64230 + 68640 + 69430 + 69070 + 68420 + 68150 + 68050 + 67880 + 67660 + 67620 + 68170 + 67800 + 63390 + 55510 + 45820 + 34020 + 19510 + 9039 + 4401 = 729,792.977
$$
6. Number of data points $n = 32$.
7. Average value:
$$\bar{x} = \frac{729792.977 \times 10^{-9}}{32} = 22,806.6555 \times 10^{-9} = 2.2807 \times 10^{-5}$$ watts.
8. Since $2.2807 \times 10^{-5}$ watts is much smaller than 125 or 167, the average value is not between 125 and 167.
**Final answer:** The average value of the given data is approximately $2.28 \times 10^{-5}$ watts, which is not between 125 and 167.