1. The problem is to find the average value of the data points from index 20 to 60 in the given "getData" column. 2. The average (mean) of a set of values $x_1, x_2, \ldots, x_n$ is given by the formula: $$\text{Average} = \frac{1}{n} \sum_{i=1}^n x_i$$ where $n$ is the number of data points. 3. Extract the values from index 20 to 60 (inclusive) from the "getData" column: - 20: 37.10E-6 - 21: 35.37E-6 - 22: 30.05E-6 - 23: 19.41E-6 - 24: 10.86E-6 - 25: 5.663E-6 - 26: 2.583E-6 - 27: 2.105E-6 - 28: 1.375E-6 - 29: 1.106E-6 - 30: 711.6E-9 - 31: 569.9E-9 - 32: 363.7E-9 - 33: 144.5E-9 - 34: 41.78E-9 - 35: 9.168E-9 - 36: 1.455E-9 - 37: 143.8E-12 - 38: 13.66E-12 - 39: 8.031E-12 - 40: 8.025E-12 - 41: 8.023E-12 - 42: 8.021E-12 - 43: 8.018E-12 - 44: 8.015E-12 - 45: 8.012E-12 - 46: 8.012E-12 - 47: 8.011E-12 - 48: 8.011E-12 - 49: 8.011E-12 - 50: 8.011E-12 - 51: 8.011E-12 - 52: 8.011E-12 - 53: 8.011E-12 - 54: 8.011E-12 - 55: 8.011E-12 - 56: 8.011E-12 - 57: 8.011E-12 - 58: 8.011E-12 - 59: 8.011E-12 - 60: 8.011E-12 4. Convert all values to a consistent unit (watts): - For example, $37.10E-6 = 3.710 \times 10^{-5}$ W - Similarly, $711.6E-9 = 7.116 \times 10^{-7}$ W - And $143.8E-12 = 1.438 \times 10^{-10}$ W 5. Sum all these values: $$S = 3.710\times10^{-5} + 3.537\times10^{-5} + 3.005\times10^{-5} + 1.941\times10^{-5} + 1.086\times10^{-5} + 5.663\times10^{-6} + 2.583\times10^{-6} + 2.105\times10^{-6} + 1.375\times10^{-6} + 1.106\times10^{-6} + 7.116\times10^{-7} + 5.699\times10^{-7} + 3.637\times10^{-7} + 1.445\times10^{-7} + 4.178\times10^{-8} + 9.168\times10^{-9} + 1.455\times10^{-9} + 1.438\times10^{-10} + 1.366\times10^{-11} + 8.031\times10^{-12} + 8.025\times10^{-12} + 8.023\times10^{-12} + 8.021\times10^{-12} + 8.018\times10^{-12} + 8.015\times10^{-12} + 8.012\times10^{-12} + 8.012\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12} + 8.011\times10^{-12}$$ 6. Calculate the sum $S \approx 1.68 \times 10^{-4}$ W (approximate sum of all values). 7. Count the number of points $n = 41$ (from index 20 to 60 inclusive). 8. Calculate the average: $$\text{Average} = \frac{S}{n} = \frac{1.68 \times 10^{-4}}{41} \approx 4.10 \times 10^{-6}$$ 9. Therefore, the average value of the data points from index 20 to 60 is approximately $4.10 \times 10^{-6}$ watts. This means the average power in that range is about 4.10 microwatts.