1. The problem asks to write +9,200 as a 16-bit unsigned value. 2. A 16-bit unsigned integer can represent values from 0 to $2^{16} - 1 = 65535$. 3. Since +9,200 is within this range, it can be represented directly. 4. To write +9,200 as a 16-bit unsigned value, convert 9,200 to binary. 5. Convert 9,200 to binary: $$9200_{10} = 10001111101000_2$$ 6. This binary number has 13 bits, so pad with leading zeros to make it 16 bits: $$00010001111101000_2$$ 7. The 16-bit unsigned representation of +9,200 is: $$0010001111101000_2$$ 8. In hexadecimal, this is: $$0x23E8$$ Final answer: +9,200 as a 16-bit unsigned value is $$0010001111101000_2$$ or $$0x23E8$$.