1. **Find the Octal equivalent of 143Hex** - Given hexadecimal: $143_{16}$ - Step 1: Convert hex to decimal $$1 \times 16^2 + 4 \times 16^1 + 3 \times 16^0 = 1 \times 256 + 4 \times 16 + 3 = 256 + 64 + 3 = 323_{10}$$ - Step 2: Convert decimal to octal Divide 323 by 8 repeatedly and record remainders: $$323 \div 8 = 40 \text{ remainder } 3$$ $$40 \div 8 = 5 \text{ remainder } 0$$ $$5 \div 8 = 0 \text{ remainder } 5$$ - Write remainders from last to first: $503_8$ **Answer:** $503_8$ 2. **List the three components of the CPU** - The CPU has three main components: 1. Arithmetic Logic Unit (ALU): Performs arithmetic and logical operations. 2. Control Unit (CU): Directs the operation of the processor. 3. Registers: Small storage locations that hold data and instructions temporarily. 3. **Evaluate $(BEE)_{16} + (ACE)_{16}$ and give the answer in binary** - Convert both hex numbers to decimal: $$BEE_{16} = 11 \times 16^2 + 14 \times 16^1 + 14 \times 16^0 = 11 \times 256 + 14 \times 16 + 14 = 2816 + 224 + 14 = 3054_{10}$$ $$ACE_{16} = 10 \times 16^2 + 12 \times 16^1 + 14 \times 16^0 = 10 \times 256 + 12 \times 16 + 14 = 2560 + 192 + 14 = 2766_{10}$$ - Add decimal values: $$3054 + 2766 = 5820_{10}$$ - Convert sum to binary: Divide by 2 and track remainders: $$5820_{10} = 1011011000100_2$$ (To confirm, can convert or use standard base10 to binary conversion.) **Answer:** $1011011000100_2$ 4. **Write a complete C program that adds integer multiples of 5 from 5 up to 100** ```c #include int main() { int sum = 0; for (int i = 5; i <= 100; i += 5) { sum += i; } printf("Sum of multiples of 5 from 5 to 100 is: %d\n", sum); return 0; } ``` This program uses a for loop starting at 5, increments by 5 each iteration until 100. It keeps a running total in the variable `sum`, then prints the result. **Answer:** Program above calculates the sum as 1050.