Complex Polar
1. **State the problem:**
Convert each complex number $z_k$ into the form $\cos\theta + i\sin\theta$ by finding the angle $\theta$.
2. **Recall the formula:**
A complex number in rectangular form $a + bi$ can be written as $\cos\theta + i\sin\theta$ where $\theta = \arg(z) = \tan^{-1}(\frac{b}{a})$.
3. **Important rules:**
- The angle $\theta$ must be adjusted based on the quadrant of $(a,b)$.
- Use exact values for common angles.
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**1) For** $z_1 = \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}i$:
- $a = \frac{\sqrt{2}}{2}$, $b = \frac{\sqrt{2}}{2}$
- $\theta = \tan^{-1}(1) = \frac{\pi}{4}$ (1st quadrant)
- So, $z_1 = \cos\frac{\pi}{4} + i\sin\frac{\pi}{4}$
**2) For** $z_2 = -\frac{1}{2} - \frac{\sqrt{3}}{2}i$:
- $a = -\frac{1}{2}$, $b = -\frac{\sqrt{3}}{2}$
- $\tan\theta = \frac{b}{a} = \frac{-\frac{\sqrt{3}}{2}}{-\frac{1}{2}} = \sqrt{3}$
- Reference angle $= \frac{\pi}{3}$
- Since $a<0$ and $b<0$, $z_2$ is in the third quadrant
- $\theta = \pi + \frac{\pi}{3} = \frac{4\pi}{3}$
- So, $z_2 = \cos\frac{4\pi}{3} + i\sin\frac{4\pi}{3}$
**3) For** $z_3 = -\frac{\sqrt{3}}{2} + \frac{1}{2}i$:
- $a = -\frac{\sqrt{3}}{2}$, $b = \frac{1}{2}$
- $\tan\theta = \frac{b}{a} = \frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = -\frac{1}{\sqrt{3}}$
- Reference angle $= \frac{\pi}{6}$
- Since $a<0$ and $b>0$, $z_3$ is in the second quadrant
- $\theta = \pi - \frac{\pi}{6} = \frac{5\pi}{6}$
- So, $z_3 = \cos\frac{5\pi}{6} + i\sin\frac{5\pi}{6}$
**4) For** $z_4 = -\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2}i$:
- $a = -\frac{\sqrt{2}}{2}$, $b = -\frac{\sqrt{2}}{2}$
- $\tan\theta = \frac{b}{a} = 1$
- Reference angle $= \frac{\pi}{4}$
- Since $a<0$ and $b<0$, $z_4$ is in the third quadrant
- $\theta = \pi + \frac{\pi}{4} = \frac{5\pi}{4}$
- So, $z_4 = \cos\frac{5\pi}{4} + i\sin\frac{5\pi}{4}$
**5) For** $z_5 = i$:
- $a = 0$, $b = 1$
- This lies on the positive imaginary axis
- $\theta = \frac{\pi}{2}$
- So, $z_5 = \cos\frac{\pi}{2} + i\sin\frac{\pi}{2}$
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**Final answers:**
$$
z_1 = \cos\frac{\pi}{4} + i\sin\frac{\pi}{4}
$$
$$
z_2 = \cos\frac{4\pi}{3} + i\sin\frac{4\pi}{3}
$$
$$
z_3 = \cos\frac{5\pi}{6} + i\sin\frac{5\pi}{6}
$$
$$
z_4 = \cos\frac{5\pi}{4} + i\sin\frac{5\pi}{4}
$$
$$
z_5 = \cos\frac{\pi}{2} + i\sin\frac{\pi}{2}
$$