Password Count 2A1395
1. **Problem statement:** We need to find the number of 6-letter passwords using distinct letters from the English alphabet where the first letter must be a vowel.
2. **Important information:**
- English alphabet has 26 letters.
- Vowels are A, E, I, O, U (5 vowels).
- Password length is 6.
- Letters must be distinct.
- First letter must be a vowel.
3. **Step 1: Choose the first letter (vowel).**
There are 5 choices for the first letter.
4. **Step 2: Choose the remaining 5 letters.**
After choosing the first vowel, 25 letters remain (26 - 1).
We need to choose 5 distinct letters from these 25.
5. **Step 3: Arrange the remaining 5 letters.**
Since order matters, we use permutations.
Number of ways to arrange 5 letters out of 25 is $$P(25,5) = \frac{25!}{(25-5)!} = \frac{25!}{20!}$$
6. **Step 4: Calculate total number of passwords.**
Total = (choices for first letter) \times (arrangements of remaining 5 letters)
$$\text{Total} = 5 \times P(25,5) = 5 \times \frac{25!}{20!}$$
7. **Step 5: Calculate numeric value.**
$$P(25,5) = 25 \times 24 \times 23 \times 22 \times 21 = 6375600$$
So,
$$\text{Total} = 5 \times 6375600 = 31878000$$
**Final answer:** There are 31,878,000 possible passwords.