1. Problem: Find how many integers $\leq 1000$ are not multiples of 4, 5, or 6. 2. Use the Inclusion-Exclusion Principle: - Total numbers from 1 to 1000: $1000$ - Multiples of 4: $\left\lfloor \frac{1000}{4} \right\rfloor = 250$ - Multiples of 5: $\left\lfloor \frac{1000}{5} \right\rfloor = 200$ - Multiples of 6: $\left\lfloor \frac{1000}{6} \right\rfloor = 166$ - Multiples of both 4 and 5 (LCM 20): $\left\lfloor \frac{1000}{20} \right\rfloor = 50$ - Multiples of both 4 and 6 (LCM 12): $\left\lfloor \frac{1000}{12} \right\rfloor = 83$ - Multiples of both 5 and 6 (LCM 30): $\left\lfloor \frac{1000}{30} \right\rfloor = 33$ - Multiples of 4, 5, and 6 (LCM 60): $\left\lfloor \frac{1000}{60} \right\rfloor = 16$ 3. Apply Inclusion-Exclusion: $$\text{Count} = 1000 - (250 + 200 + 166) + (50 + 83 + 33) - 16$$ 4. Calculate step-by-step: - Sum of singles: $250 + 200 + 166 = 616$ - Sum of doubles: $50 + 83 + 33 = 166$ So, $$\text{Count} = 1000 - 616 + 166 - 16 = 1000 - 616 + 150 = 534$$ 5. Therefore, there are $\boxed{534}$ integers less than or equal to 1000 that are not multiples of 4, 5, or 6.