1. **State the problem:** We need to find the current through the 2-Ω resistor between points a and b in the given circuit using the superposition principle. 2. **Identify sources:** The circuit has two current sources: 24 A on the left branch and 6 A on the right branch. 3. **Apply superposition principle:** Analyze the circuit twice, each time considering only one current source active and the other replaced by an open circuit (since they are current sources). --- **Case 1: Only 24 A source active** - The 6 A source is replaced by an open circuit. - The 24 A current flows through the left branch with 4 Ω resistor. - The right branch is open, so no current flows there. - The 2 Ω resistor is connected between points a and b on the top branch. Since the right branch is open, the current through the 2 Ω resistor is zero in this case. --- **Case 2: Only 6 A source active** - The 24 A source is replaced by an open circuit. - The 6 A current flows through the right branch with 6 Ω resistor. - The left branch is open, so no current flows there. Again, the 2 Ω resistor is connected between points a and b on the top branch. Since the left branch is open, the current through the 2 Ω resistor is zero in this case as well. --- 4. **Combine results:** The total current through the 2 Ω resistor is the sum of currents from both cases. $$I_{2\Omega} = 0 + 0 = 0\,\text{A}$$ 5. **Conclusion:** The current through the 2 Ω resistor is zero amperes. This means no current flows through the 2 Ω resistor under the given conditions using superposition.