Ph Calculation F8F31A
1. The first problem asks to determine the pH of a solution with a hydrogen ion concentration of $0.000023$.
2. The formula for pH is:
$$\text{pH} = -\log_{10}[\text{H}^+]$$
where $[\text{H}^+]$ is the hydrogen ion concentration.
3. Substitute the given concentration:
$$\text{pH} = -\log_{10}(0.000023)$$
4. Calculate the logarithm:
$$0.000023 = 2.3 \times 10^{-5}$$
$$\log_{10}(2.3 \times 10^{-5}) = \log_{10}(2.3) + \log_{10}(10^{-5}) = \log_{10}(2.3) - 5$$
5. Approximate $\log_{10}(2.3) \approx 0.3617$, so:
$$\text{pH} = -(0.3617 - 5) = 5 - 0.3617 = 4.6383$$
6. Rounded to two decimal places, the pH is approximately $4.64$.
7. Therefore, the answer $4.64$ is correct.
Since the user asked if the answers are correct and provided multiple problems, only the first problem is solved here as per instructions.