1. **State the problem:** Find the equation of the tangent line to the function $f(x) = 3 - 2x$ at the point $(-1, 5)$. 2. **Recall the formula:** The equation of the tangent line at $x = a$ is given by: $$y = f(a) + f'(a)(x - a)$$ where $f'(a)$ is the derivative of $f(x)$ evaluated at $x = a$. 3. **Find the derivative:** Since $f(x) = 3 - 2x$, the derivative is: $$f'(x) = -2$$ 4. **Evaluate the derivative at $x = -1$:** $$f'(-1) = -2$$ 5. **Use the point $(-1, 5)$ and slope $-2$ in the tangent line formula:** $$y = 5 + (-2)(x - (-1)) = 5 - 2(x + 1)$$ 6. **Simplify the equation:** $$y = 5 - 2x - 2 = 3 - 2x$$ 7. **Final answer:** The equation of the tangent line is: $$y = 3 - 2x$$ Note: The tangent line is the same as the original function because $f(x)$ is linear.