Sin Ln Function
1. The problem is to understand and analyze the function $$y = \frac{\sin x}{\ln x}$$.
2. First, identify the domain of the function. Since \(\ln x\) is defined for \(x > 0\), the domain is \(x > 0\).
3. Additionally, \(\ln x = 0\) at \(x = 1\), so \(y\) is undefined at \(x = 1\).
4. The function represents the sine of \(x\) divided by the natural logarithm of \(x\).
5. Points of interest include zeros of \(y\), which occur when \(\sin x = 0\) and \(x > 0\) with \(x \neq 1\).
6. Zeros of \(\sin x\) are at \(x = n\pi\) where \(n\) is an integer greater than 0 and \(n\pi \neq 1\).
7. The function has vertical asymptotes at \(x = 1\) since \(\ln x = 0\) there.
8. As \(x \to 0^+\), \(\ln x \to -\infty\), and since \(\sin x \approx x\), \(y \to 0\).
9. As \(x \to \infty\), \(\ln x\) grows slowly and \(\sin x\) oscillates between -1 and 1, so \(y\) oscillates, decreasing in amplitude.
10. The function can be plotted to visualize intercepts and extrema.
Final function: $$y = \frac{\sin x}{\ln x}$$.