1. The problem asks to rearrange the expression $2 + \sqrt{x+4}$ in the form $y = ...$ before integrating. 2. We start by defining the function: $$y = 2 + \sqrt{x+4}$$ 3. This expresses $y$ explicitly in terms of $x$, which is suitable for integration. 4. To integrate, you would compute: $$\int y \, dx = \int \left(2 + \sqrt{x+4}\right) dx$$ 5. Break the integral into parts: $$\int 2 \, dx + \int \sqrt{x+4} \, dx = 2x + \int (x+4)^{1/2} \, dx$$ 6. Use a substitution for the second integral, let $u = x+4$, so $du = dx$: $$\int u^{1/2} \, du = \frac{2}{3} u^{3/2} + C = \frac{2}{3} (x+4)^{3/2} + C$$ 7. Therefore, the integral is: $$2x + \frac{2}{3} (x+4)^{3/2} + C$$ 8. Final answer: $$\int \left(2 + \sqrt{x+4}\right) dx = 2x + \frac{2}{3} (x+4)^{3/2} + C$$