Subjects calculus

Limits At 5 93Ad00

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Limits At 5 93Ad00


1. The problem asks for the value of $f(5)$ and the limits of $f(x)$ as $x$ approaches 5 from the left, right, and both sides. 2. From the graph description, near $x=5$, the bottom-right quadrant curve approaches $y=0$ from below as $x$ approaches 5 from the left and continues upward beyond 5. 3. Therefore: - $f(5)$ is the value of the function at $x=5$, which from the graph is $0$. - $\lim_{x \to 5^-} f(x) = 0$ (approaching 0 from below). - $\lim_{x \to 5^+} f(x)$ is greater than 0 as the curve shoots upward beyond 5, so the right-hand limit is greater than 0. - Since the left and right limits are not equal, $\lim_{x \to 5} f(x)$ does not exist. Final answers: $$f(5) = 0$$ $$\lim_{x \to 5^-} f(x) = 0$$ $$\lim_{x \to 5^+} f(x) \neq 0$$ $$\lim_{x \to 5} f(x) \text{ does not exist}$$