1. The problem is to find the limits of the function $3t^2$ as $t$ approaches $\sin x$ and $1$. 2. First, evaluate the limit as $t \to \sin x$: $$\lim_{t \to \sin x} 3t^2 = 3(\sin x)^2 = 3\sin^2 x$$ This is because the function $3t^2$ is continuous, so we can substitute $t = \sin x$ directly. 3. Next, evaluate the limit as $t \to 1$: $$\lim_{t \to 1} 3t^2 = 3(1)^2 = 3$$ Again, by continuity, substitute $t = 1$ directly. 4. Therefore, the limits are: - As $t \to \sin x$, the limit is $3\sin^2 x$. - As $t \to 1$, the limit is $3$. Final answers: $$\lim_{t \to \sin x} 3t^2 = 3\sin^2 x$$ $$\lim_{t \to 1} 3t^2 = 3$$