1. The problem is to find the limit $$\lim_{x \to 0} \frac{\sin x}{x}$$. 2. We use the standard limit rule: $$\lim_{x \to 0} \frac{\sin x}{x} = 1$$. 3. This is a fundamental limit in calculus and is often proved using the squeeze theorem or geometric arguments. 4. Therefore, the answer is $$1$$. This completes the solution for the first limit problem.