1. **State the problem:** We need to find the limit $$\lim_{x \to a} 2 \sin x$$. 2. **Recall the limit property:** The sine function is continuous everywhere, so $$\lim_{x \to a} \sin x = \sin a$$. 3. **Apply the limit to the function:** Since multiplication by a constant is continuous, we have $$\lim_{x \to a} 2 \sin x = 2 \lim_{x \to a} \sin x = 2 \sin a.$$ 4. **Final answer:** $$\boxed{2 \sin a}$$