Integral Quadratic 04Bb4E
1. **State the problem:** Evaluate the integral $$\int \frac{dx}{x^2 + 12x + 45}$$.
2. **Rewrite the quadratic expression:** Complete the square for the denominator:
$$x^2 + 12x + 45 = (x^2 + 12x + 36) + 9 = (x + 6)^2 + 3^2$$.
3. **Recall the integral formula:** For constants $a$ and $b$,
$$\int \frac{dx}{x^2 + a^2} = \frac{1}{a} \arctan\left(\frac{x}{a}\right) + C$$.
4. **Apply substitution:** Let $u = x + 6$, so $du = dx$. The integral becomes
$$\int \frac{du}{u^2 + 3^2}$$.
5. **Use the formula:** Substitute $a = 3$:
$$\int \frac{du}{u^2 + 3^2} = \frac{1}{3} \arctan\left(\frac{u}{3}\right) + C$$.
6. **Back-substitute:** Replace $u$ with $x + 6$:
$$\frac{1}{3} \arctan\left(\frac{x + 6}{3}\right) + C$$.
**Final answer:**
$$\int \frac{dx}{x^2 + 12x + 45} = \frac{1}{3} \arctan\left(\frac{x + 6}{3}\right) + C$$.
This matches the bottom-right box in the image, confirming the correct integral evaluation.