1. **State the problem:** We need to evaluate the integral $$\int \frac{1}{\sin y} \, dy.$$ 2. **Rewrite the integral:** Recall that $$\frac{1}{\sin y} = \csc y,$$ so the integral becomes $$\int \csc y \, dy.$$ 3. **Recall the standard integral formula:** The integral of $$\csc y$$ is known: $$\int \csc y \, dy = -\ln \left| \csc y + \cot y \right| + C,$$ where $$C$$ is the constant of integration. 4. **Write final answer:** Therefore, $$\int \frac{1}{\sin y} \, dy = -\ln \left| \csc y + \cot y \right| + C.$$