1. Stated problem: Evaluate the integral $$\int \frac{1}{\sin y} \, dy$$. 2. Rewrite the integrand using the cosecant function: $$\int \csc y \, dy$$. 3. Recall the integral formula: $$\int \csc y \, dy = -\ln \left| \csc y + \cot y \right| + C$$ where $C$ is the constant of integration. 4. Therefore, the solution is $$\int \frac{1}{\sin y} \, dy = -\ln \left| \csc y + \cot y \right| + C$$. 5. This result is derived using trigonometric identities and standard integral techniques for cosecant. Final answer: $$\boxed{\int \frac{1}{\sin y} \, dy = -\ln \left| \csc y + \cot y \right| + C}$$