Graph Limit Behavior
1. Sketch and analyze $f(x) = \frac{1}{x}$.
- Problem: Graph $f(x) = \frac{1}{x}$ and identify discontinuities.
- Formula: $f(x) = \frac{1}{x}$.
- Important: The function is undefined where denominator is zero.
- Work: Denominator zero at $x=0$, so discontinuity at $x=0$.
- Explanation: The graph has vertical asymptote at $x=0$ and is continuous elsewhere.
2. Graph $f(x) = |x|$ and check continuity.
- Problem: Is $f(x) = |x|$ continuous everywhere?
- Formula: $f(x) = |x|$.
- Important: Absolute value is continuous everywhere.
- Work: No points of discontinuity.
- Explanation: The graph is a V-shape continuous for all real $x$.
3. Sketch $f(x) = \cot(x)$ and mark discontinuities.
- Problem: Identify discontinuities of $f(x) = \cot(x)$.
- Formula: $\cot(x) = \frac{\cos(x)}{\sin(x)}$.
- Important: Discontinuities where $\sin(x) = 0$.
- Work: $\sin(x) = 0$ at $x = k\pi$, $k \in \mathbb{Z}$.
- Explanation: Vertical asymptotes at multiples of $\pi$.
4. Graph $f(x) = \sqrt{x}$ and discuss continuity domain.
- Problem: Domain and continuity of $f(x) = \sqrt{x}$.
- Formula: $f(x) = \sqrt{x}$.
- Important: Defined for $x \geq 0$.
- Work: Continuous on $[0, \infty)$.
- Explanation: Not defined for $x<0$, continuous on domain.
5. For $f(x) = \ln(|x|)$, show continuity.
- Problem: Where is $f(x) = \ln(|x|)$ continuous?
- Formula: $f(x) = \ln(|x|)$.
- Important: $\ln$ defined for positive arguments.
- Work: $|x| > 0$ means $x \neq 0$.
- Explanation: Continuous on $(-\infty,0) \cup (0,\infty)$.
6. Sketch $f(x) = \frac{x^2 - 9}{x - 3}$ and identify discontinuity at $x=3$.
- Problem: Type of discontinuity at $x=3$.
- Formula: $f(x) = \frac{x^2 - 9}{x - 3} = \frac{(x-3)(x+3)}{x-3}$.
- Important: Simplify for $x \neq 3$.
- Work: $f(x) = x + 3$ for $x \neq 3$.
- Explanation: Removable discontinuity (hole) at $x=3$.
7. Graph $f(x) = \csc x$ and discuss behavior near 0.
- Problem: Behavior of $f(x) = \csc x = \frac{1}{\sin x}$ near $x=0$.
- Important: $\sin x = 0$ at $x=0$.
- Work: Vertical asymptote at $x=0$.
- Explanation: Function tends to $\pm \infty$ near 0, discontinuous at 0.
8. Sketch piecewise function:
$f(x) = \begin{cases} x + 2, & x < 0 \\ x^2, & x \geq 0 \end{cases}$
- Problem: Is $f$ continuous at 0?
- Work: Left limit $= 0 + 2 = 2$.
- Right limit $= 0^2 = 0$.
- $f(0) = 0$.
- Explanation: Limits differ, so discontinuous at 0.
9. Graph $f(x) = e^x$ and check continuity.
- Problem: Is $f(x) = e^x$ continuous for all real $x$?
- Important: Exponential function continuous everywhere.
- Explanation: Continuous on $(-\infty, \infty)$.
10. Sketch $f(x) = -\frac{1}{x^2 + 1}$ and identify asymptotes and continuity.
- Problem: Asymptotes and continuity of $f(x)$.
- Important: Denominator $x^2 + 1 > 0$ for all real $x$.
- Work: No vertical asymptotes.
- Horizontal asymptote: $y \to 0^-$ as $x \to \pm \infty$.
- Explanation: Continuous everywhere, no vertical asymptotes, horizontal asymptote at $y=0$.
Final answers summarized:
- $f(x) = \frac{1}{x}$ discontinuous at $x=0$.
- $f(x) = |x|$ continuous everywhere.
- $f(x) = \cot x$ discontinuous at $x = k\pi$.
- $f(x) = \sqrt{x}$ continuous on $[0, \infty)$.
- $f(x) = \ln(|x|)$ continuous on $(-\infty,0) \cup (0,\infty)$.
- $f(x) = \frac{x^2 - 9}{x - 3}$ removable discontinuity at $x=3$.
- $f(x) = \csc x$ discontinuous at $x = k\pi$, behavior near 0 is vertical asymptote.
- Piecewise $f$ discontinuous at 0.
- $f(x) = e^x$ continuous everywhere.
- $f(x) = -\frac{1}{x^2 + 1}$ continuous everywhere, horizontal asymptote $y=0$.