Subjects calculus

Function 2 Intervals

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Function 2 Intervals


1. **State the problem:** Find the intervals where the function (2) is increasing, decreasing, and constant. Then find its domain and range. 2. **Analyze the graph description for function (2):** - The function has a horizontal line segment ending at the closed point $(-4,4)$. - Then it drops down to the point $(0,0)$. - Next, a curved segment goes from $(0,4)$ downwards ending in an open circle at $(3,-5)$. - Finally, a rising line starts from the point $(3,0)$ extending to the right. 3. **Determine intervals of increase, decrease, and constancy:** - From the left to $x=-4$, the function is constant at $y=4$ (horizontal line segment). - From $x=-4$ to $x=0$, the function decreases from $4$ to $0$. - From $x=0$ to $x=3$, the function decreases further from $4$ (at $x=0$) down to $-5$ (open circle at $x=3$). - From $x=3$ onwards, the function increases starting at $y=0$. 4. **Write intervals explicitly:** - Constant: $(-\infty, -4]$ - Decreasing: $[-4,0]$ and $(0,3)$ - Increasing: $[3, \infty)$ 5. **Find the domain:** - The function is defined from $x=-\infty$ to $x=\infty$ (assuming the graph extends indefinitely on both sides). - So, domain is $(-\infty, \infty)$. 6. **Find the range:** - The highest value is $4$ (at $x \leq -4$ and at $x=0$). - The lowest value is $-5$ (open circle at $x=3$, so $-5$ is not included). - The function attains $0$ at $x=0$ and $x=3$. - Since $-5$ is an open circle, the range is $(-5,4]$. **Final answers:** - Increasing on $[3, \infty)$ - Decreasing on $[-4,0]$ and $(0,3)$ - Constant on $(-\infty, -4]$ - Domain: $(-\infty, \infty)$ - Range: $(-5,4]$