File Size Compression
1. **Problem Statement:** We have two functions:
$$f(n) = n \ln\left(\frac{10}{n}\right)$$
and
$$h(n) = \frac{1}{\sqrt{n + c}}$$
where $n$ represents the original file size in MB, and $c$ is a constant. We want to analyze $f(n)$ on the interval $[1,10]$ to find where compression is most and least effective, i.e., find the extrema of $f(n)$ in this interval.
2. **Understanding the function $f(n)$:**
- $f(n)$ is a product of $n$ and the natural logarithm of $\frac{10}{n}$.
- The natural logarithm function $\ln(x)$ is defined for $x > 0$.
- Since $n$ is in $[1,10]$, $\frac{10}{n}$ is positive, so $f(n)$ is well-defined.
3. **Finding critical points of $f(n)$:**
We find where the derivative $f'(n)$ is zero or undefined to locate extrema.
Using the product rule:
$$f(n) = n \ln\left(\frac{10}{n}\right) = n (\ln 10 - \ln n) = n \ln 10 - n \ln n$$
Then,
$$f'(n) = \frac{d}{dn}(n \ln 10) - \frac{d}{dn}(n \ln n) = \ln 10 - (\ln n + 1) = \ln 10 - \ln n - 1$$
Set $f'(n) = 0$:
$$\ln 10 - \ln n - 1 = 0 \implies \ln n = \ln 10 - 1$$
Exponentiate both sides:
$$n = e^{\ln 10 - 1} = 10 e^{-1} = \frac{10}{e} \approx 3.6788$$
4. **Determine the nature of the critical point:**
Calculate the second derivative:
$$f''(n) = -\frac{1}{n}$$
At $n = \frac{10}{e}$, since $n > 0$, $f''(n) = -\frac{1}{n} < 0$, so $f(n)$ has a local maximum there.
5. **Evaluate $f(n)$ at the endpoints and critical point:**
- At $n=1$:
$$f(1) = 1 \times \ln(10/1) = \ln 10 \approx 2.3026$$
- At $n=10$:
$$f(10) = 10 \times \ln(10/10) = 10 \times \ln 1 = 0$$
- At $n=\frac{10}{e}$:
$$f\left(\frac{10}{e}\right) = \frac{10}{e} \times \ln\left(\frac{10}{\frac{10}{e}}\right) = \frac{10}{e} \times \ln e = \frac{10}{e} \times 1 = \frac{10}{e} \approx 3.6788$$
6. **Interpretation:**
- The maximum compression effectiveness (maximum $f(n)$) occurs at $n = \frac{10}{e} \approx 3.6788$ MB.
- The least effective compression is at $n=10$ MB where $f(n)=0$.
7. **About $h(n) = \frac{1}{\sqrt{n + c}}$:**
- This function decreases as $n$ increases because the denominator grows.
- The constant $c$ shifts the function horizontally.
- Without a specific $c$, we cannot analyze further.
**Final answer:**
- Maximum of $f(n)$ at $n = \frac{10}{e} \approx 3.6788$ MB.
- Minimum of $f(n)$ at $n=10$ MB.