1. **State the problem:** We are given two functions of variable $n$: $$y = n^3 - 1$$ $$z = 1 - n^2$$ We want to find the derivative $$\frac{dy}{dz}$$ where $$n \neq 0$$. 2. **Recall the chain rule:** The derivative $$\frac{dy}{dz}$$ can be written as $$\frac{dy}{dz} = \frac{dy/dn}{dz/dn}$$. 3. **Calculate $$\frac{dy}{dn}$$:** $$\frac{dy}{dn} = \frac{d}{dn}(n^3 - 1) = 3n^2$$. 4. **Calculate $$\frac{dz}{dn}$$:** $$\frac{dz}{dn} = \frac{d}{dn}(1 - n^2) = -2n$$. 5. **Divide the derivatives:** $$\frac{dy}{dz} = \frac{3n^2}{-2n} = -\frac{3n^2}{2n}$$. 6. **Simplify the expression:** Since $$n \neq 0$$, $$-\frac{3n^2}{2n} = -\frac{3}{2}n$$. 7. **Final answer:** $$\frac{dy}{dz} = -\frac{3}{2}n$$. **Answer choice:** B) $$-\frac{3}{2}n$$