Continuity Graph
1. The problem asks to determine the continuity of the function $g(x)$ at specific points based on the graph description.
2. At $x = -2$, the graph has a closed dot at $(-2,0)$ and the segment starts there, so $g$ is continuous from the right at $x = -2$ (correct).
3. At $x = -1$, there is an open circle at $(-1,1)$ on the segment from $-2$ to $-1$, and also an open circle at $(-1,1)$ starting the horizontal line to $0$. Since the function value is not defined at $-1$ (open circle), $g$ is not continuous at $x = -1$ (correct).
4. At $x = 0$, there is a closed dot at $(0,1)$ on the horizontal line and an open circle at $(0,0)$ on the upward sloping line. The function value at $0$ is $1$, but the limit from the left is $1$ and from the right is $0$, so $g$ is not continuous at $0$ (correct).
5. At $x = 1$, there is an open circle at $(1,2)$ on the upward sloping line and a closed dot at $(1,0)$ on the curve. The function value is $0$, but the limit from the left is $2$, so $g$ is not continuous at $1$ (correct).
6. At $x = 2$, there is an open circle at $(2,0)$ on the curve, so the function is not defined at $2$, meaning $g$ is discontinuous at $2$ (correct).
7. At $x = 3$, the graph is not defined beyond $2$, so $g$ is not continuous from the right at $3$ (correct).
Final corrected answers:
1. Continuous from the right at $x = -2$: ✓
2. Continuous at $x = -1$: ✗
3. Continuous at $x = 0$: ✗
4. Continuous at $x = 1$: ✗
5. Discontinuous at $x = 2$: ✓
6. Continuous from the right at $x = 3$: ✗