Antiderivative 2X 8B63F0
1. Find an antiderivative of the function $2x$.
2. The formula for the antiderivative of $x^n$ where $n \neq -1$ is:
$$\int x^n \, dx = \frac{x^{n+1}}{n+1} + C$$
where $C$ is the constant of integration.
3. Applying this formula to $2x = 2x^1$:
$$\int 2x \, dx = 2 \int x^1 \, dx = 2 \cdot \frac{x^{1+1}}{1+1} + C = 2 \cdot \frac{x^2}{2} + C = x^2 + C$$
4. So, an antiderivative of $2x$ is:
$$x^2 + C$$
5. To check, differentiate $x^2 + C$:
$$\frac{d}{dx}(x^2 + C) = 2x$$
which matches the original function.
Final answer: $x^2 + C$