1. **Stating the problem:** We are given two functions representing acceleration, $R''(t) = -16.8t + 23.2$ and $R''(t) = -330t + 266$, and asked to interpret their meaning. 2. **Understanding the notation:** $R''(t)$ denotes the second derivative of a position function $R(t)$ with respect to time $t$, which represents acceleration. 3. **Interpreting the first function:** $R''(t) = -16.8t + 23.2$ means acceleration changes linearly with time $t$. The term $-16.8t$ indicates acceleration decreases as time increases, and $23.2$ is the initial acceleration at $t=0$. 4. **Interpreting the second function:** $R''(t) = -330t + 266$ also shows acceleration changing linearly with time but at a much faster rate. The coefficient $-330$ means acceleration decreases very rapidly as time increases, and $266$ is the initial acceleration at $t=0$. 5. **Summary:** Both functions describe acceleration that decreases over time starting from a positive initial value. The second function represents a scenario with much stronger acceleration changes compared to the first. Final answer: The functions $R''(t) = -16.8t + 23.2$ and $R''(t) = -330t + 266$ represent acceleration as a linear function of time, decreasing over time with different rates and initial values.