1. The problem is to find the sum of the given list of numbers. 2. The formula for the sum of a list of numbers $x_1, x_2, \ldots, x_n$ is: $$\text{Sum} = \sum_{i=1}^n x_i$$ 3. We add all the numbers together step-by-step. 4. Adding all the numbers given (including repeated values) results in: $$3368 + 3368 + 1837 + 1837 + 4130 + 4130 + 4493 + 4493 + 3745 + 3745 + 575 \times 10 + 3338 \times 4 + 2730 \times 2 + 5250 \times 2 + 1875 \times 2 + 2620 \times 6 + 2310 \times 2 + 3740 \times 4 + 3080 \times 3 + 4490 + 3745 \times 2 + 2720 \times 2 + 4130 \times 2 + 590 \times 10 + 4760 + 2293 \times 2 + 5240 \times 2 + 3430 \times 2 + 4000 + 3080 \times 2 + 4240 + 2730 \times 4 + 2243 \times 3 + 2790 + 2240 \times 2 + 840 \times 5 + 3360 \times 2 + 4560 \times 2 + 5400 \times 2 + 3040 \times 2 + 4480 \times 2 + 1540 \times 2 + 2000 \times 2 + 2300 + 980 \times 3$$ 5. Calculating the sum stepwise or using a calculator yields the total sum: $$\text{Sum} = 222,091$$ 6. Therefore, the sum of all the numbers provided is **222091**. This method involves careful addition of all repeated and individual numbers to get the final total.