1. The problem states the equation chain: $1992 + 4 = 1996 + 3 = 1999$. 2. First, evaluate each sum separately to verify the equality. 3. Calculate $1992 + 4$: $$1992 + 4 = 1996$$ 4. Calculate $1996 + 3$: $$1996 + 3 = 1999$$ 5. The chain shows $1992 + 4 = 1996$ and $1996 + 3 = 1999$, so the full chain is $1992 + 4 = 1996 = 1996 + 3 = 1999$. 6. This means the first equality is $1992 + 4 = 1996$, which is true. 7. The second equality $1996 + 3 = 1999$ is also true. 8. Therefore, the chain $1992 + 4 = 1996 + 3 = 1999$ is valid as the sums evaluate correctly. Final answer: The equalities hold true as $1992 + 4 = 1996$ and $1996 + 3 = 1999$.