1. The problem asks for the sum of all the digits in the integers from 1 to 20. 2. To solve this, we need to add each digit of every number from 1 to 20. 3. Let's list the digits: - From 1 to 9, the digits are just the numbers themselves: 1, 2, 3, 4, 5, 6, 7, 8, 9. - From 10 to 19, each number has two digits: 1 and the second digit (0 to 9). - Number 20 has digits 2 and 0. 4. Sum digits from 1 to 9: $$1+2+3+4+5+6+7+8+9=45$$ 5. Sum digits from 10 to 19: - The tens digit is 1 for each number, so sum of tens digits = $$1 \times 10 = 10$$ - The units digits go from 0 to 9, sum is $$0+1+2+3+4+5+6+7+8+9=45$$ - Total sum for 10 to 19 is $$10 + 45 = 55$$ 6. Sum digits of 20: $$2 + 0 = 2$$ 7. Total sum of digits from 1 to 20 is: $$45 + 55 + 2 = 102$$ Therefore, the sum of all the digits in the integers from 1 to 20 is **102**.