1. The problem is to multiply the mixed numbers $-3 \frac{1}{4}$ and $2 \frac{2}{3}$. 2. Convert each mixed number to an improper fraction. - $-3 \frac{1}{4} = -\left(3 + \frac{1}{4}\right) = -\frac{13}{4}$. - $2 \frac{2}{3} = 2 + \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3}$. 3. Multiply the improper fractions: $$-\frac{13}{4} \times \frac{8}{3} = -\frac{13 \times 8}{4 \times 3} = -\frac{104}{12}$$ 4. Simplify the fraction $-\frac{104}{12}$ by dividing numerator and denominator by their greatest common divisor $4$: $$-\frac{104 \div 4}{12 \div 4} = -\frac{26}{3}$$. 5. Convert back to a mixed number: - Divide $26$ by $3$: $26 \div 3 = 8$ remainder $2$. - So, $-\frac{26}{3} = -8 \frac{2}{3}$. Final answer: $-8 \frac{2}{3}$.