1. The problem is to multiply the mixed numbers $3\frac{1}{2}$ and $3\frac{4}{5}$. 2. Convert each mixed number to an improper fraction: - $3\frac{1}{2} = \frac{(3\times 2) + 1}{2} = \frac{6 + 1}{2} = \frac{7}{2}$ - $3\frac{4}{5} = \frac{(3\times 5) + 4}{5} = \frac{15 + 4}{5} = \frac{19}{5}$ 3. Multiply the improper fractions: $$\frac{7}{2} \times \frac{19}{5} = \frac{7 \times 19}{2 \times 5} = \frac{133}{10}$$ 4. Convert the improper fraction back to a mixed number: - Divide 133 by 10: $133 \div 10 = 13$ remainder $3$ - So, $\frac{133}{10} = 13\frac{3}{10}$ Final answer: $13\frac{3}{10}$