Subjects arithmetic

Multiplication Division 83B47D

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Multiplication Division 83B47D


1. **Problem A:** Cleo has 3 times as many bananas as Arianna. Cleo has 6 bananas. Find how many bananas Arianna has. 2. **Formula:** If Cleo has 3 times as many bananas as Arianna, then: $$\text{Cleo's bananas} = 3 \times \text{Arianna's bananas}$$ 3. **Set up equation:** $$6 = 3 \times a$$ where $a$ is Arianna's bananas. 4. **Solve for $a$:** $$a = \frac{6}{3} = 2$$ 5. **Answer:** Arianna has 2 bananas. 1. **Problem B:** Dylan has 6 oranges. Jane has 3 times as many oranges as Dylan. Find how many oranges Jane has. 2. **Formula:** $$\text{Jane's oranges} = 3 \times \text{Dylan's oranges}$$ 3. **Set up equation:** $$j = 3 \times 6$$ 4. **Calculate:** $$j = 18$$ 5. **Answer:** Jane has 18 oranges. 1. **Problem C:** Liam has 3 cherries. Brian has 6 times as many cherries as Liam. Find how many cherries Brian has. 2. **Formula:** $$\text{Brian's cherries} = 6 \times \text{Liam's cherries}$$ 3. **Set up equation:** $$b = 6 \times 3$$ 4. **Calculate:** $$b = 18$$ 5. **Answer:** Brian has 18 cherries. 1. **Problem D:** Tina has 3 more peaches than Charlie. Charlie has 6 peaches. Find how many peaches Tina has. 2. **Formula:** $$\text{Tina's peaches} = \text{Charlie's peaches} + 3$$ 3. **Set up equation:** $$t = 6 + 3$$ 4. **Calculate:** $$t = 9$$ 5. **Answer:** Tina has 9 peaches. 1. **Problem E:** Jaclyn has 6 times as many grapes as Kaitlyn. Kaitlyn has 3 grapes. Find how many grapes Jaclyn has. 2. **Formula:** $$\text{Jaclyn's grapes} = 6 \times \text{Kaitlyn's grapes}$$ 3. **Set up equation:** $$j = 6 \times 3$$ 4. **Calculate:** $$j = 18$$ 5. **Answer:** Jaclyn has 18 grapes. 1. **Bar Model Problem:** Karl takes 4 times as many photos as Jack. Jack has 5 photos. Karl has 4 groups of 5 photos, total 20. 2. **Equation to find $p$, the number of photos Jack took:** Since Karl's photos = 4 times Jack's photos, and Karl has 20 photos: $$20 = 4 \times p$$ 3. **Solve for $p$:** $$p = \frac{20}{4} = 5$$ 4. **Answer:** The correct equation is option C) $20 \div 4 = p$.