1. **State the problem:** Given a cross-like number arrangement with vertical numbers 7 (top) and 3 (bottom), and horizontal numbers 3 and 10 (left and right respectively), calculate the vertical and horizontal sums. 2. **Vertical sum:** Add top and bottom numbers: $$7 + 3 = 10$$ 3. **Horizontal sum:** Add left and right numbers: $$3 + 10 = 13$$ --- 1. Vertical: 10 (top), 20 (bottom) Horizontal: 20, 40 2. Vertical sum: $$10 + 20 = 30$$ 3. Horizontal sum: $$20 + 40 = 60$$ --- 1. Vertical: 30 (top), 6 (bottom) Horizontal: 6, 18 2. Vertical sum: $$30 + 6 = 36$$ 3. Horizontal sum: $$6 + 18 = 24$$ --- 1. Vertical: 10.2 (top), 2 (bottom) Horizontal: 2, 3.8 2. Vertical sum: $$10.2 + 2 = 12.2$$ 3. Horizontal sum: $$2 + 3.8 = 5.8$$ --- 1. Vertical: 6 (top), 7 (bottom) Horizontal: 7, 2 2. Vertical sum: $$6 + 7 = 13$$ 3. Horizontal sum: $$7 + 2 = 9$$ --- 1. Vertical: 10 (top), 8 (bottom) Horizontal: 8, 22 2. Vertical sum: $$10 + 8 = 18$$ 3. Horizontal sum: $$8 + 22 = 30$$ --- 1. Vertical: 7 (top), 50 (bottom) Horizontal: 50, 3, 40 (three numbers horizontally, interpret as two separate segments 50-3 and 3-40) 2. Vertical sum: $$7 + 50 = 57$$ 3. Horizontal sums: $$50 + 3 = 53$$ $$3 + 40 = 43$$ --- 1. Vertical: 8.5 (top), 15 (bottom) Horizontal: 15, 4 2. Vertical sum: Convert 8 1/2 = 8.5 $$8.5 + 15 = 23.5$$ 3. Horizontal sum: $$15 + 4 = 19$$ --- 1. Vertical: 10 (top), 10 (bottom) Horizontal: 10, 12 2. Vertical sum: $$10 + 10 = 20$$ 3. Horizontal sum: $$10 + 12 = 22$$ --- 1. Vertical: 15 (top), 10 (bottom) Horizontal: 10, 2 2. Vertical sum: $$15 + 10 = 25$$ 3. Horizontal sum: $$10 + 2 = 12$$