1. **State the problem:** Calculate the difference between the mixed numbers $8 \frac{2}{8}$ and $3 \frac{3}{8}$. 2. **Convert mixed numbers to improper fractions:** $8 \frac{2}{8} = 8 + \frac{2}{8} = \frac{8 \times 8}{8} + \frac{2}{8} = \frac{64}{8} + \frac{2}{8} = \frac{66}{8}$ $3 \frac{3}{8} = 3 + \frac{3}{8} = \frac{3 \times 8}{8} + \frac{3}{8} = \frac{24}{8} + \frac{3}{8} = \frac{27}{8}$ 3. **Subtract the improper fractions:** $\frac{66}{8} - \frac{27}{8} = \frac{66 - 27}{8} = \frac{39}{8}$ 4. **Convert the result back to a mixed number:** Divide 39 by 8: $39 \div 8 = 4$ remainder $7$ So, $\frac{39}{8} = 4 \frac{7}{8}$ 5. **Final answer:** $8 \frac{2}{8} - 3 \frac{3}{8} = 4 \frac{7}{8}$