Mixed Number Subtraction
1. Stating the problems:
Calculate the following subtractions of mixed numbers:
- TELUR: $4 \frac{2}{10} - 2 \frac{1}{5}$
- JAMUR ENOKI: $5 \frac{2}{5} - 3 \frac{1}{3}$
- SAYUR: $4 \frac{5}{6} - 2 \frac{1}{6}$
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2. TELUR: $4 \frac{2}{10} - 2 \frac{1}{5}$
- Convert mixed numbers to improper fractions:
$$4 \frac{2}{10} = 4 + \frac{2}{10} = \frac{40}{10} + \frac{2}{10} = \frac{42}{10}$$
$$2 \frac{1}{5} = 2 + \frac{1}{5} = \frac{10}{5} + \frac{1}{5} = \frac{11}{5}$$
- Find common denominator for $\frac{42}{10}$ and $\frac{11}{5}$:
The denominators are 10 and 5, common denominator is 10.
- Convert $\frac{11}{5}$ to denominator 10:
$$\frac{11}{5} = \frac{11 \times 2}{5 \times 2} = \frac{22}{10}$$
- Subtract:
$$\frac{42}{10} - \frac{22}{10} = \frac{42 - 22}{10} = \frac{20}{10} = 2$$
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3. JAMUR ENOKI: $5 \frac{2}{5} - 3 \frac{1}{3}$
- Convert mixed numbers to improper fractions:
$$5 \frac{2}{5} = 5 + \frac{2}{5} = \frac{25}{5} + \frac{2}{5} = \frac{27}{5}$$
$$3 \frac{1}{3} = 3 + \frac{1}{3} = \frac{9}{3} + \frac{1}{3} = \frac{10}{3}$$
- Find common denominator for 5 and 3:
The least common denominator is 15.
- Convert fractions:
$$\frac{27}{5} = \frac{27 \times 3}{5 \times 3} = \frac{81}{15}$$
$$\frac{10}{3} = \frac{10 \times 5}{3 \times 5} = \frac{50}{15}$$
- Subtract:
$$\frac{81}{15} - \frac{50}{15} = \frac{31}{15} = 2 \frac{1}{15}$$
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4. SAYUR: $4 \frac{5}{6} - 2 \frac{1}{6}$
- Convert mixed numbers to improper fractions:
$$4 \frac{5}{6} = 4 + \frac{5}{6} = \frac{24}{6} + \frac{5}{6} = \frac{29}{6}$$
$$2 \frac{1}{6} = 2 + \frac{1}{6} = \frac{12}{6} + \frac{1}{6} = \frac{13}{6}$$
- Denominators are the same (6), subtract directly:
$$\frac{29}{6} - \frac{13}{6} = \frac{16}{6} = 2 \frac{4}{6} = 2 \frac{2}{3}$$
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Final answers:
- TELUR: $2$
- JAMUR ENOKI: $2 \frac{1}{15}$
- SAYUR: $2 \frac{2}{3}$