1. **State the problem:** Mose has a total of 7680 shillings and wants to change all the money into notes and coins using the least number of notes and coins. 2. **Identify the denominations:** The options mention notes and coins of 1000, 500, 200, 100, 50, 20, and 10 shillings. 3. **Goal:** Minimize the total number of notes and coins. 4. **Analyze each option by calculating the total amount and counting the number of notes and coins:** - a. 7×1000 + 6×100 + 1×50 + 1×20 + 1×10 = 7000 + 600 + 50 + 20 + 10 = 7680; total pieces = 7 + 6 + 1 + 1 + 1 = 16 - b. 7×1000 + 3×200 + 1×50 + 3×10 = 7000 + 600 + 50 + 30 = 7680; total pieces = 7 + 3 + 1 + 3 = 14 - c. 7×1000 + 1×500 + 1×100 + 1×50 + 1×20 + 1×10 = 7000 + 500 + 100 + 50 + 20 + 10 = 7680; total pieces = 7 + 1 + 1 + 1 + 1 + 1 = 12 - d. 7×1000 + 2×200 + 2×100 + 8×10 = 7000 + 400 + 200 + 80 = 7680; total pieces = 7 + 2 + 2 + 8 = 19 - e. 14×500 + 6×100 + 8×10 = 7000 + 600 + 80 = 7680; total pieces = 14 + 6 + 8 = 28 5. **Conclusion:** Option c uses the least number of notes and coins (12 pieces). **Final answer:** Option c is correct.