1. **State the problem:** You need to calculate the sums of the following additions: - Five sums of the form $$a + \frac{1}{10}$$ where $$a$$ is an integer. - Seven sums of the form $$1 + \frac{5}{32}$$. 2. **Calculate each sum in the first group:** - $$1 + \frac{1}{10} = \frac{10}{10} + \frac{1}{10} = \frac{11}{10} = 1.1$$ - $$5 + \frac{1}{10} = \frac{50}{10} + \frac{1}{10} = \frac{51}{10} = 5.1$$ - $$2 + \frac{1}{10} = \frac{20}{10} + \frac{1}{10} = \frac{21}{10} = 2.1$$ - $$3 + \frac{1}{10} = \frac{30}{10} + \frac{1}{10} = \frac{31}{10} = 3.1$$ - $$4 + \frac{1}{10} = \frac{40}{10} + \frac{1}{10} = \frac{41}{10} = 4.1$$ 3. **Calculate each sum in the second group:** Since all are $$1 + \frac{5}{32}$$, calculate once: - $$1 + \frac{5}{32} = \frac{32}{32} + \frac{5}{32} = \frac{37}{32} = 1.15625$$ All seven sums equal $$1.15625$$. **Final answers:** - First group: 1.1, 5.1, 2.1, 3.1, 4.1 - Second group: Seven times 1.15625