Problem: Compute $2\frac{1}{5}+\frac{1}{4}-3\frac{1}{5}\times\frac{2}{4}\div2\frac{4}{5}$.\n1. Convert the mixed numbers to improper fractions.\n$2\frac{1}{5}=\frac{11}{5}$.\n$3\frac{1}{5}=\frac{16}{5}$.\n$2\frac{4}{5}=\frac{14}{5}$.\n2. Compute the product and the quotient in the subtraction term from left to right.\n$\frac{16}{5}\times\frac{2}{4}=\frac{32}{20}=\frac{8}{5}$.\n$\frac{8}{5}\div\frac{14}{5}=\frac{8}{5}\times\frac{5}{14}=\frac{8}{14}=\frac{4}{7}$.\n3. Substitute this result back into the expression.\n$\frac{11}{5}+\frac{1}{4}-\frac{4}{7}$.\n4. Convert each fraction to the common denominator 140.\n$\frac{11}{5}=\frac{308}{140}$.\n$\frac{1}{4}=\frac{35}{140}$.\n$\frac{4}{7}=\frac{80}{140}$.\n5. Add and subtract the numerators.\n$\frac{308}{140}+\frac{35}{140}-\frac{80}{140}=\frac{308+35-80}{140}=\frac{263}{140}$.\n6. Convert to a mixed number and simplify if possible.\n$\frac{263}{140}=1\frac{123}{140}$, and $\frac{123}{140}$ is in lowest terms.\nFinal answer: $\frac{263}{140}=1\frac{123}{140}$.\n