1. The problem asks to write each number, 36 and 42, in expanded form. 2. Expanded form means expressing a number as the sum of each digit multiplied by its place value. 3. For 36, the digits are 3 and 6, where 3 is in the tens place and 6 is in the ones place. 4. So, 36 in expanded form is $$30 + 6$$ because $3 \times 10 = 30$ and $6 \times 1 = 6$. 5. For 42, the digits are 4 and 2, where 4 is in the tens place and 2 is in the ones place. 6. So, 42 in expanded form is $$40 + 2$$ because $4 \times 10 = 40$ and $2 \times 1 = 2$. 7. Thus, the expanded forms are: - 36 = $$30 + 6$$ - 42 = $$40 + 2$$