1. **State the problem:** We need to divide 5 by 4 and then divide 56 by 4, finding the quotient and remainder for each. 2. **Divide 5 by 4:** - 4 goes into 5 once (since $4 \times 1 = 4$). - Subtract $4$ from $5$ to find the remainder: $5 - 4 = 1$. - So, quotient = 1 and remainder = 1. 3. **Divide 56 by 4:** - 4 goes into 56 exactly $\frac{56}{4} = 14$ times with no remainder. - So, quotient = 14 and remainder = 0. 4. **Summary:** - For $5 \div 4$, quotient = 1, remainder = 1. - For $56 \div 4$, quotient = 14, remainder = 0. This shows how division can result in a remainder when the divisor does not evenly divide the dividend, and how to interpret the quotient and remainder in such cases.