1. **Stating the problem:** We need to divide the given three-digit numbers by the two-digit divisors using long division. 2. **Formula and rules:** Division is the process of finding how many times the divisor fits into the dividend. We perform long division step-by-step, subtracting multiples of the divisor from parts of the dividend. 3. **Calculations:** (1) Divide 180 by 83: - 83 goes into 180 twice (2 × 83 = 166) - Subtract 166 from 180: 180 - 166 = 14 - Quotient: 2 remainder 14 (2) Divide 252 by 83: - 83 goes into 252 three times (3 × 83 = 249) - Subtract 249 from 252: 252 - 249 = 3 - Quotient: 3 remainder 3 (3) Divide 415 by 83: - 83 goes into 415 five times (5 × 83 = 415) - Subtract 415 from 415: 415 - 415 = 0 - Quotient: 5 remainder 0 (4) Divide 567 by 83: - 83 goes into 567 six times (6 × 83 = 498) - Subtract 498 from 567: 567 - 498 = 69 - Quotient: 6 remainder 69 (5) Divide 180 by 84: - 84 goes into 180 twice (2 × 84 = 168) - Subtract 168 from 180: 180 - 168 = 12 - Quotient: 2 remainder 12 (6) Divide 252 by 84: - 84 goes into 252 three times (3 × 84 = 252) - Subtract 252 from 252: 252 - 252 = 0 - Quotient: 3 remainder 0 (7) Divide 415 by 84: - 84 goes into 415 four times (4 × 84 = 336) - Subtract 336 from 415: 415 - 336 = 79 - Quotient: 4 remainder 79 (8) Divide 567 by 84: - 84 goes into 567 six times (6 × 84 = 504) - Subtract 504 from 567: 567 - 504 = 63 - Quotient: 6 remainder 63 **Final answers:** (1) $2\ \text{R}14$ (2) $3\ \text{R}3$ (3) $5\ \text{R}0$ (4) $6\ \text{R}69$ (5) $2\ \text{R}12$ (6) $3\ \text{R}0$ (7) $4\ \text{R}79$ (8) $6\ \text{R}63$