1. The problem asks us to compare the fractions $\frac{1}{3}$ and $\frac{1}{4}$. 2. To compare fractions, one common way is to find a common denominator. The denominators here are 3 and 4. 3. The least common denominator (LCD) of 3 and 4 is 12. 4. Convert each fraction to an equivalent fraction with denominator 12: $$\frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12}$$ $$\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}$$ 5. Now compare $\frac{4}{12}$ and $\frac{3}{12}$. Since $4 > 3$, it follows that: $$\frac{4}{12} > \frac{3}{12}$$ 6. Therefore: $$\frac{1}{3} > \frac{1}{4}$$ Final answer: $\boxed{\frac{1}{3} > \frac{1}{4}}$