1. **Problem 1: Bananas sold by Millie** Millie had 600 bananas. She sold \(\frac{1}{5}\) of them on Saturday and \(\frac{3}{8}\) of the remaining bananas on Sunday. **a) How many bananas did she sell on Saturday?** Calculate \(\frac{1}{5}\) of 600: $$\frac{1}{5} \times 600 = \frac{1}{5} \times \frac{600}{1} = \frac{600}{5} = 120$$ So, she sold 120 bananas on Saturday. **b) How many bananas did she sell on Sunday?** First, find the remaining bananas after Saturday: $$600 - 120 = 480$$ Now, calculate \(\frac{3}{8}\) of 480: $$\frac{3}{8} \times 480 = \frac{3}{8} \times \frac{480}{1} = \frac{1440}{8} = 180$$ So, she sold 180 bananas on Sunday. **c) How many bananas did she sell on both days?** Add the bananas sold on Saturday and Sunday: $$120 + 180 = 300$$ So, she sold 300 bananas in total. **d) How many bananas does she have now?** Subtract the total sold from the original amount: $$600 - 300 = 300$$ She has 300 bananas left. --- 2. **Problem 2: Luas lahan pertanian Paman (Area of Paman's farm)** Paman has a rectangular farm with width \(5 \frac{3}{5}\) hm and length \(3 \frac{3}{4}\) hm. Convert mixed numbers to improper fractions: Width: $$5 \frac{3}{5} = \frac{5 \times 5 + 3}{5} = \frac{25 + 3}{5} = \frac{28}{5}$$ Length: $$3 \frac{3}{4} = \frac{3 \times 4 + 3}{4} = \frac{12 + 3}{4} = \frac{15}{4}$$ Calculate the area of the rectangle: $$\text{Area} = \text{width} \times \text{length} = \frac{28}{5} \times \frac{15}{4} = \frac{28 \times 15}{5 \times 4} = \frac{420}{20} = 21$$ So, the area of Paman's farm is 21 hm\(^2\).