1. **Problem statement:** Given the function $h(x) = 7x^4 - 10^3 + 3^2 + 3x -3$ and knowing that one zero of $h(x)$ is $x=1$, find the remaining zeros. 2. **Simplify the polynomial:** Evaluate the constants: $$-10^3 = -1000,$$ $$3^2 = 9.$$ So the polynomial becomes: $$h(x) = 7x^4 - 1000 + 9 + 3x - 3 = 7x^4 + 3x - 994.$$ 3. **Verify zero at $x=1$:** Substitute $x=1$ into $h(x)$: $$h(1) = 7(1)^4 + 3(1) - 994 = 7 + 3 - 994 = -984 eq 0.$$ This shows $x=1$ is not a zero of the simplified polynomial, which contradicts the problem statement. 4. **Reconsider the original expression:** Possibly the polynomial was intended as: $$h(x) = 7x^4 - 10x^3 + 3^2 + 3x -3,$$ where $10^3$ means $10 imes x^3$ (a common shorthand). Simplifying constants: $$3^2 = 9,$$ so $$h(x) = 7x^4 - 10x^3 + 9 + 3x -3 = 7x^4 - 10x^3 + 3x + 6.$$ 5. **Check zero at $x=1$ for revised polynomial:** $$h(1) = 7 - 10 + 3 + 6 = 6,$$ still not zero. Try $x=-1$: $$h(-1) = 7(1) + 10 + (-3) + 6 = 20,$$ no zero. 6. **Assuming the problem intended $h(x)=7x^4 - 10x^3 + 9x^2 + 3x -3$ (including $3^2$ meaning $9x^2$):** $$h(x) = 7x^4 - 10x^3 + 9x^2 + 3x - 3.$$ 7. **Verify zero at $x=1$ for this polynomial:** $$h(1) = 7 - 10 + 9 + 3 - 3 = 6,$$ no zero. Try $x=1$ is zero in question; maybe a typo. 8. **Since $x=1$ is given as a zero, use polynomial division:** Divide $h(x)=7x^4 - 10^3 + 3^2 + 3x - 3$ by $(x-1)$ to find quotient polynomial and then find remaining zeros. 9. **Use synthetic division with $x=1$: ** For coefficients: $$7, 0, 0, 3, - (10^3) + 3^2 -3$$ But terms are unclear; need correct polynomial. **Conclusion:** The problem statement contains ambiguities in the polynomial expression making exact zeros indeterminate. Please clarify the exact polynomial. Since the polynomial and zero information are unclear, further steps cannot proceed accurately.