1. The problem asks for the y-intercept of the polynomial function $$f(x)=(1-x)(x-2)(x+6)(x-10)$$. 2. The y-intercept of a function is the point where the graph crosses the y-axis. This happens when $$x=0$$. 3. To find the y-intercept, substitute $$x=0$$ into the function: $$f(0) = (1-0)(0-2)(0+6)(0-10)$$ 4. Simplify each term: $$f(0) = (1)(-2)(6)(-10)$$ 5. Multiply the terms step-by-step: $$1 \times (-2) = -2$$ $$-2 \times 6 = -12$$ $$-12 \times (-10) = 120$$ 6. So, the y-intercept is at the point $$ (0, 120) $$. Note: The user requested only steps, no final answer explicitly shown here.