1. **State the problem:** We have two box sizes, small and large, selling identical chocolate pieces. Large box price = 2 \times small box price. Selling price per gram in large box is 12% less than that in small box. Find the percentage by which the weight of chocolate in the large box exceeds that in the small box. 2. **Let variables:** Let \(P_s\) = price of small box \(W_s\) = weight of chocolate in small box (grams) \(P_l = 2P_s\) (large box price) \(W_l\) = weight of chocolate in large box (grams) 3. **Price per gram relation:** Price per gram small box = \(\frac{P_s}{W_s}\) Price per gram large box = \(\frac{P_l}{W_l} = \frac{2P_s}{W_l}\) Large box price per gram is 12% less than small box price per gram: $$\frac{2P_s}{W_l} = (1 - 0.12) \times \frac{P_s}{W_s} = 0.88 \times \frac{P_s}{W_s}$$ 4. **Find relation between weights:** $$\frac{2P_s}{W_l} = 0.88 \times \frac{P_s}{W_s}$$ Divide both sides by \(P_s\): $$\frac{2}{W_l} = \frac{0.88}{W_s}$$ Rearranged: $$W_l = \frac{2 W_s}{0.88} = \frac{2}{0.88} W_s = \frac{200}{88} W_s = \frac{25}{11} W_s \approx 2.2727 W_s$$ 5. **Calculate percentage increase:** Percentage increase: $$\left(\frac{W_l - W_s}{W_s}\right) \times 100 = \left(\frac{\frac{25}{11} W_s - W_s}{W_s}\right) \times 100 = \left(\frac{25}{11} - 1\right) \times 100 = \frac{14}{11} \times 100 \approx 127.27\%$$ 6. **Final answer:** Weight of chocolate in the large box exceeds that in the small box by approximately 127%. **Answer choice:** B) 127