1. **State the problem:** We have two pools with initial amounts of water and different rates of filling. We want to find after how many minutes the two pools will have the same amount of water and how much water that will be. 2. **Write the expressions for the amount of water in each pool:** - First pool: $1582 + 34.5t$ - Second pool: $1900 + 21.25t$ 3. **Set the amounts equal to find $t$:** $$1582 + 34.5t = 1900 + 21.25t$$ 4. **Solve for $t$:** Subtract $21.25t$ from both sides: $$1582 + 34.5t - 21.25t = 1900$$ Simplify: $$1582 + 13.25t = 1900$$ Subtract 1582 from both sides: $$13.25t = 1900 - 1582$$ $$13.25t = 318$$ Divide both sides by 13.25: $$t = \frac{318}{13.25} \approx 24$$ 5. **Find the amount of water in each pool at $t \approx 24$ minutes:** First pool: $$1582 + 34.5 \times 24 = 1582 + 828 = 2410$$ Second pool: $$1900 + 21.25 \times 24 = 1900 + 510 = 2410$$ 6. **Answer:** - The pools will have the same amount of water after approximately **24 minutes**. - At that time, each pool will contain approximately **2410 liters** of water.